(x^2+x)(x^2+x-3)+2=0

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Solution for (x^2+x)(x^2+x-3)+2=0 equation: 


Simplifying
(x2 + x)(x2 + x + -3) + 2 = 0

Reorder the terms:
(x + x2)(x2 + x + -3) + 2 = 0

Reorder the terms:
(x + x2)(-3 + x + x2) + 2 = 0

Multiply (x + x2) * (-3 + x + x2)
(x(-3 + x + x2) + x2(-3 + x + x2)) + 2 = 0
((-3 * x + x * x + x2 * x) + x2(-3 + x + x2)) + 2 = 0
((-3x + x2 + x3) + x2(-3 + x + x2)) + 2 = 0
(-3x + x2 + x3 + (-3 * x2 + x * x2 + x2 * x2)) + 2 = 0
(-3x + x2 + x3 + (-3x2 + x3 + x4)) + 2 = 0

Reorder the terms:
(-3x + x2 + -3x2 + x3 + x3 + x4) + 2 = 0

Combine like terms: x2 + -3x2 = -2x2
(-3x + -2x2 + x3 + x3 + x4) + 2 = 0

Combine like terms: x3 + x3 = 2x3
(-3x + -2x2 + 2x3 + x4) + 2 = 0

Reorder the terms:
2 + -3x + -2x2 + 2x3 + x4 = 0

Solving
2 + -3x + -2x2 + 2x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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